CHEMISTRY – GRADE NINE
LEVEL 3-DIMENSIONAL ANALYSIS
REVIEW GUIDE
Let’s start with the simplest guide: Identifying metric units.
Length Units:
1 in = 2.54 cm
1 ft = 12 in
1 m/mi = 1.609 km
Mass units:
1 lb = 453.6g
2.2 lb = 1 kg
Volume units:
1 gal = 3.79 L
1.057 qt (quarts) = 1 L
For solving these units, please remember these:
Positive side: The Gingerman killed his dad.
Negative side: Don’t call the police nor my mom.
Length Units: mm (millimeter) km (kilometer) dm (decameter) pm (picometer)
Nm (nanometer) dm (decimeter) mm (megameter) mm (micrometer) cm
(centimeter)
Mass Units: gt (gigatons) mg (megaton) t (tonne) kg (kilogram) g (gram) mg
(milligram) mg (microgram) ng (nanogram) pg (picogram)
Volume Units: milliliter (ml) centiliter (cl) deca/deciliter (dl) hectoliter (hl)
Try to remember! – How to solve dimensional analysis
2500 gal to ml
Unit map: 2500 ml  ? gal
- We have to scale out the unit-map first before we move-on the expanded
version.
Expanded Map: ml  l  gal
Since ml (milliliter) and gal (gallon) is involved with volume and original unit for
all volumes is L(liter/s), you have to use 1 gal = 3.79L.
Conversion Factors:
2500 𝑔𝑎𝑙 ×
3.79 𝐿 103 𝑚𝑙
×
1 𝑔𝑎𝑙
1𝐿
As you can see here, we have our gal (gallon) as our primary unit,
We are required to multiply to 1 gal = 3.79L, by identifying it, we have to place
gal (gallon) as our main unit for cancelling gal to gal.
After cancelling gal to gal, we now have L (liter) as our primary unit.
So its 2500 x 3.79 now. Next, we cancel the L to L and get left with 10^3 ml.
So our final equation is: 2500 x 3.79 x 10^3 =
9.47500 x 10^6 (9.47 x 10^4). (as our final answer).
Now you know it, please try to answer the file in the drive file.
END.